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By convention, \(P\) is power, \(I\) is current, \(R\) is resistance, and \(E\) is Voltage (Electro-motive force).
The Power Law states: \(P = I \times E\). Ohm's law states that \(E = I \times R\). Combining those to remove E, we get a restatement of the Power Law as \(P = I \times (I \times R)\), or \(P = I^2 \times R\)
So in this case:
\[P = (.02)^2 \times 10,000\] \[P = 0.0004 \times 10,000\]
Thus
\[P = 4 \text{ watts}\]
Last edited by kd7bbc. Register to edit
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